1)
N(3.2,0.6)
x = lifespan
to find P(x > 4) convert x to N(0,1) using z statistic: z = (x - mean)/SD = (x -3.2)/0.6.
P(x > 4) = P(z > (4 - 3.2)/0.6 = P(z > 1.33) = 1 - P(z < 1.33) = 1 - 0.9082 = 0.0918.
2)
N(117.8,2.3)
once again use z-statisitc.
For this problem, z = (x - mean)/SD = (x-117.8(/2.3
For 82%, we look up z-score corresponding to 0.82 from standard normal probability table = 0.915
so 0.915 = (x - 117.8)/2.3
x = 119.9
3) For this problem x = length N(262.6,2.2).
For this problem, z = (x - mean)/SD = (x - 262.6)/2.2
Want to find P(x < 269.2) = P(z < (269.2 - 262.6)/2.2) = P(z < 3) = 0.9987