In a titration of 25.00 mL of X solution, 32.55 mL of 0.8323 M Y solution are required to reach the end-point. What is the concentration of the 25.00 mL of X? X + 3Y → 3W + Z

Answer 1

X + 3Y ==> 3W + Z

moles of Y used in the titration = 32.55 ml x 1 L/1000 ml x 0.8323 mol/L = 0.02709 moles Y

moles X neutralized = 0.02709 mol Y x 1 mol X / 3 mol Y = 0.009030 moles X

Concentration of X = 0.009030 moles X / 0.02500 L = 0.3612 M