If 28.1 g of Ar(g) occupies a volume of 4.56 L, what volume will 1.15 moles of Ne(g) occupy at the same temperature and pressure?

Answer 1

If the temperature and the pressure are the same (constant), then the volume of an idea gas depends only on the number of moles of that gas. This is seen from the Ideal Gas Law PV = nRT and if P, T and R are all constant, you are left with V proportional to n

28.1 g Ar x 1 mol Ar/39.9 g = 0.704 moles Ar

moles Ne = 1.15 moles

ratio of moles Ne/moles Ar = 1.15 mol/0.704 moles = 1.63

Volume occupied by Ne = 1.63 x 4.56 L = 7.45 L