J.R. S. answered 10/27/20
Ph.D. University Professor with 10+ years Tutoring Experience
For this problem we can use q = mC∆T
q = heat = ?
m = mass = 51.13 g
C = specific heat capacity = 7.93 J/gº
∆T = change in temperature = 3.01º
q = (51.13 g)(7.93 J/gº)(3.01º)
q = -1220 J (negative sign indicating heat released from reaction to surroundings = exothermic)