Write an equation of a line that passes through point A(4,-5) and is parallel to the line y=4x-3

Answer 1

y=4x-3 has slope = to the coefficient of the x term = 4

all parallel lines have the same slope.

y=4x + b, where b can be any real number, so just plug in the point (4,-5) into the general equation

y=4x+b = -5 = 4(4) + b

-5 = 16 + b

-21 = b

b = -21 = the y intercept, so the equation is

y=4x -21

Answer 2

Hello, Isabella,

"parallel to the line y=4x-3" means that the new line will have the same slope, in this case "4." So we can write y = 4x + I, where I is the intercept for the new line. We find I by entering the coordinates (4, -5) and solving for I .

-5 = 4*4 + I

I = -21

So the new equation is y = 4x - 21

Bob

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