In ∆ABC, if m∠A is thirteen less than m∠C and m∠B is eleven less than four times m∠C, find the measure of each angle.

Answer 1

m<A = m<C - 13

m<B = 4*m<C - 11

The sum of the measures of the angles of a triangle are 180

m<A + m<B + m<C = 180

m<C -13 + 4*m<C - 11 + m<c = 180

6m<C - 24 = 180

6m<C = 204

m<C = 34

m<A = m<C-13 = 34- 13 = 21

m<B = 4*m<C - 11 = 4*34 - 11 = 125