energy and temp change to specific heat

Question

In the laboratory a student finds that it takes 3.05×10³ Joules to increase the temperature of 14.9 grams of gaseous hydrogen from 21.3 to 36.8 degrees Celsius.

The specific heat of hydrogen he has measured is  J/g

Answer 1

q = mC∆T

q = heat = 3.05x10³ J

m = mass = 14.9 g

C = specific heat = ?

∆T = change in temperature = 36.8 - 21.3 = 15.5º

Plug in the values and solve for C (specific heat)

C = q/m∆T = 3.05x10³ J/(149 g)(15.5º) = J/gº