J.R. S. answered 10/23/20
Ph.D. University Professor with 10+ years Tutoring Experience
36.7 g Sn x 1 mol Sn/118.7 g = 0.3092 moles
0.3092 moles x 7.07 kJ/mol = 2.19 kJ (3 sig. figs.)
Natalie Y.
asked 10/23/20Given the following information for tin, Sn (at 1 atm), calculate the amount of heat in kJ needed (at 1 atm) to melt a 36.7-g sample of solid tin at its normal melting point of 232 °C.
boiling point = 2.27×103 °C |
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melting point = 232 °C |
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specific heat liquid = 0.243 J/g°C |
Answer In kJ
J.R. S. answered 10/23/20
Ph.D. University Professor with 10+ years Tutoring Experience
36.7 g Sn x 1 mol Sn/118.7 g = 0.3092 moles
0.3092 moles x 7.07 kJ/mol = 2.19 kJ (3 sig. figs.)
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