J.R. S. answered 10/23/20
Ph.D. University Professor with 10+ years Tutoring Experience
1) moles 1.5232 g x 1 mol/126.07 g = 0.012082 moles (5 s.f.)
2) 0.0120822 moles/0.2500 L = 0.04833 M (4 s.f.)
Yes, your answer is correct.
Ooyeon O.
asked 10/23/20Calculate the number of moles of oxalic acid and the molarity of the oxalic acid solution.
Molar mass of H2C2O4•2H2O 126.07 g/mol
Mass of H2C2O4•2H2O 1.5232g
1) No. of moles of H2C2O4•2H2O _______?________ mol
Volume of H2C2O4•2H2O solution 250.0 mL
2) Molarity H2C2O4 standard solution _____?____M
1) Answer is 1.5232 x 1 mol /126.07 g/mol = 0.012082 mol
2) Answer is 0.012082 / 0.25L = 0.048328 M
I didn't exactly understand the "standard solution" What is mean?
My answer is correct or not?
and sometimes, I don't know how many decimal places I have to write down. How to write the answer correctly form?
J.R. S. answered 10/23/20
Ph.D. University Professor with 10+ years Tutoring Experience
1) moles 1.5232 g x 1 mol/126.07 g = 0.012082 moles (5 s.f.)
2) 0.0120822 moles/0.2500 L = 0.04833 M (4 s.f.)
Yes, your answer is correct.
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Ooyeon O.
Thank you for helping me study10/23/20