What is the de Broglie wavelength, in centimeters, of a 12.4 g hummingbird flying at 40 mph

Answer 1

λ = h / mv

λ = deBroglie wavelength in meters

h = Planck's constant = 6.626x10^-34 Jsec

m = mass in kg = 12.4 g x 1 kg/1000 g = 0.0124 kg

v = velocity in meters/sec = 40 mile/hr x 1 hr/3600 sec x 1609 meter/1 mile = 17.88 m/sec

λ = 6.626x10^-34 Jsec / (0.0124 kg)(17.88 m/sec) = 2.99x10^-33 m

2.99x10^-33 m x 10² cm/m = 2.99x10^-31 cm