J.R. S. answered 10/22/20
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = ?
m = mass = 51.13 g
C = specific heat = 4.11 J/gº
∆T = change in temperature = 3.01º
q = (51.13 g)(4.11 J/gº)(3.01º)
q = 633 J (3 sig. figs.)