How does the electric force between two particles change if one of the particle’s charge is reduced by a factor of 3?

Answer 1

Force = K(q1q2/r2) Coulomb's Law

K = constant

q1 = charge 1

q2 = charge 2

r = radius

If charge is the only variable, then the force will be 1/3 the original force if the charge on one particle (q) is reduced by a factor of 3. For example...

q1 = 3

q2 = 1

r = 2

F = (3)(1)/4 = 0.75

F = (1)(1)/4 = 0.25 if q1 is reduced by a factor of 3