J.R. S. answered 10/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
First, we should write the correctly balanced equation for the reaction taking place...
Cu(s) + 2HNO3 ==> Cu(NO3)2 + H2(g)
0.503g....xs.............? g................
moles Cu present = 0.503 g x 1 mol Cu/63.5 g = 0.007921 moles Cu
moles of Cu(NO3)2 formed = 0.007921 mol Cu x 1 mol Cu(NO3)2 / mol Cu = 0.007921 mol Cu(NO3)2 formed
theoretical mass of Cu(NO3)2 = 0.007921 mol x 187.6 g/mol = 1.47 g (3 sig. figs.)