College Math: Help

Question

You wish to test the following claim () at a significance level of .      

      

You obtain a sample of size in which there are 210 successful observations. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)

test statistic = __________

What is the p-value for this sample? (Report answer accurate to four decimal places.)

p-value = __________

Answer 1

Ok so to get the test statistic: Since you assume a normal distribution, you use the formula x-u/sd.

Now, we have to use our sample proportion 210/314, and use that as our value for x, and u is the assumed mean proportion. So as a result, we have (210/314-.73)/sqrt((p*1-p)/n), where p is the proportion 210/314. That would get us our test stat.

To get the p-value, you find P(Z<z), where z is the test statistic.

That should help you out!