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Bri L.

asked • 11d

Given the thermochemical equations

X2+3Y2⟶2XY3Δ𝐻1=−390 kJ


X2+2Z2⟶2XZ2Δ𝐻2=−160 kJ


2Y2+Z2⟶2Y2ZΔ𝐻3=−270

Calculate the change in enthalpy for the reaction.


4XY3+7Z2⟶6Y2Z+4XZ2


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