Hot107.8 g unknown substance initially at 181.9°C is placed in 35.0 mL of water initially at 25.0°C and the system is allowed to reach thermal equilibrium.final temperature of the system is 78.8°C.

Question

Find the specific heat (j/gxc)

Answer 1

heat lost by unknown = heat gained by water

(107.8 g)(C)(103.1º) = (35 g)(4.184 J/gº)(53.8º)

C = 0.709 J/gº

By now you should be able to follow the above procedure knowing q = mC∆T