Write the equation of a line that is perpendicular to y=-x-6and that passes through the point(-9,-4)

Answer 1

In equation y = -x -6, the slope is -1. Perpendicular line has slope equal to negative reciprocal of -1, which is 1.

point-intercept equation of line:

y - (-4) = 1 * (x--9)

compute slope intercept equation of line:

y + 4 = x + 9

y = x + 5

Answer 2

Write the equation of a line that is perpendicular to y = -x-6 and passes through point (-9,-4)

A couple things you need to know to do this problem.

1. Perpendicular slope is the negative reciprocal to the line it is perpendicular to
2. You need to know how to solve for Y=M(X) + B with a slope and one point

So...

1. Perpendicular slope to the given line Y = -X - 6, would be the negative reciprocal of -1, so +1
2. M = 1
3. Y = 1(X) + B, passing through (-9,-4); so plug in the X and Y value (from the coordinate) and solve for B
4. -4 = 1(-9) + B; -4 = -9 + B; 5 = B
5. Y = X + 5 (note: the slope of 1 is understood, you don't have to write 1X)