J.R. S. answered 10/16/20
Ph.D. University Professor with 10+ years Tutoring Experience
H2C2O4 + 2 NaOH → Na2C2O4 + 2 H2O ... balanced equation
From this balanced equation we see that it takes TWO moles of NaOH for every ONE mole of oxalic acid.
Therefore to neutralize 0.000835 moles oxalic acid, it will take TWICE as many moles of NaOH.
0.000835 moles oxalic acid x 2 mole NaOH/mol oxalic acid = 0.00167 moles NaOH needed
Ooyeon O.
Thank you for your detailed explanation.10/16/20