Write an equation for a line perpendicular to y = − 4 x − 1 and passing through the point (8,5)

Question

pls help me................................

Answer 1

The equation of our line will be y=Ax+B where we have to determine the constants A, B. Since we want our line to be perpendicular to the line y=-4x-1 we must have that (-4)A=-1 which implies that A=1/4. To find B we use that the point (8,5) belongs on our line and hence, we must have 5=(1/4)8+B which is the same as 5=2+B. Therefore, B=3 and our line has the equation y=(1/4)x+3.

Answer 2

Given line

y= -4x - 1

Slope = -4

Equation of line perpendicular to this line

y=( 1/4) x+b

As slope is -1/m

Now as line passes through (8,5)

Plug it in

5 = (1/4)8 +b

5= 2+ b

Gives b = 3

So the equation of line will be

y = (1/4) x +3

or 4y =x+12