Use z-score formula z - (x - mean)/standard deviation, where x = weight, 1103 = mean and 82 = SD.
so z = (x - 1103)/82
a) Look up z closest to 0.42 probability, then plug that value in for z in formula and solve for x.
b) Look up z closest to 0.97 probability, then plug that value in for z in formula and solve for x.
c) IQR is 75th percentile - 25th percentile
Look up z closest to 0.75 and 0.25 probabilities, then plug those values into z in formula for solve for x values then take the difference of those x values.