What is an equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15 ?

Answer 1

The given line can be rewritten as y=(-1/3)x+5. The general equation of a line is y=Ax+B where the constants A and B are to be found. Since we want our line to be parallel to the given line they need to have the same slope which implies that A=-1/3. In order to find the value of B we need to solve the equation 1=(-1/3)6+B which gives that B=3. Hence, the desired equation is y=(-1/3)x+3.