J.R. S. answered 10/15/20
Ph.D. University Professor with 10+ years Tutoring Experience
pH + pOH = 14 MEMORIZE THIS RELATIONSHIP
pOH = -log [OH-]
We can solve this problem by 2 different methods
(1). pOH = -log [OH-]
[OH-] = 1x10-2.97 = 1.07x10-3 M
[H+][OH-] = 1x10-14
[H+] = 1x10-14 / 1.07x10-3 = 9.35x10-12 M
(2). pH + pOH = 14
pH = 14 - pOH
pH = 14 - 2.97
pH = 11.03
pH = -log [H]
[H+] = 1x10-11.03
[H+] = 9.3x10-12 M