J.R. S. answered 10/15/20
Ph.D. University Professor with 10+ years Tutoring Experience
Ba(CHO2)2 is barium formate. This salt is formed from the reaction of a STRONG BASE, Ba(OH)2 and a WEAK ACID, formic acid, HCOOH.
The pH of the salt will be basic.
Dissolving the salt in water results in hydrolysis, and the equation is ...
Ba(CHO2)2 + 2H2O ==> Ba(OH)2 + 2HCOOH
or more appropriately, we would write HCOO- + H2O ==> HCOOH + OH-
HCOO- is a conjugate base of HCOOH and so the equilibrium expression is Kb = [HCOOH][OH-]/[HCOO-]