What is the molarity of the acetic acid?

Question

Using the procedure in Determination of an Equilibrium Constant, a student combines equimolar amounts of acetic acid and ethanol to react as shown by the following equation.

acetic acid + ethanol ⇌ ethyl acetate + water

To determine the initial concentration of acetic acid, 1.00mL of the resulting mixture was titrated with 0.2950 M NaOH requiring 31.25 mL

What is the molarity of the acetic acid?

Answer 1

acetic acid = CH3COOH

sodium hydroxide = NaOH

Reaction: CH3COOH + NaOH ==> H2O + CH3COONa

mole NaOH needed = moles CH3COOH present = 31.25 ml x 1 L/1000 ml x 0.2950 mol/L = 0.0092188 moles

Molarity of CH3COOH = 0.0092188 moles/0.001 L = 9.22 M