What is the equilibrium concentration (M) of ethyl acetate?

Question

Consider the balanced reversible reaction of acetic acid with ethanol.

acetic acid + ethanol ⇌ ethyl acetate + water

When you react 8.44M acetic acid with 8.44M  ethanol, the equilibrium concentration of acetic acid is 3.06M 

What is the equilibrium concentration (M) of ethyl acetate?

Answer 1

acetic acid + ethanol ===> ethyl acetate + water

8.44................8.44.....................0.........................Initial

-x...................-x.......................+x..........................Change

3.06...............3.06..................?............................Equilibrium

For acetic acid and ethanol to go from 8.44 to 3.06, the value of x must be 5.38, i.e. 8.44 - 3.06.

Thus equilibrium concentration of ethyl acetate will be 5.38 M