Given a normally distributed dataset with a mean of 100 and standard deviation of 15, what percentage of points is above 130?

Answer 1

p (X>130)

On TI-84

2nd VARS 2 (normalcdf)

Lower 130

Upper 1 E 99 (The E is 2nd , )

Mean 100

SD 15

Paste

Answer 0.022750062

Alternatively p (X>130) = p (Z>2).

On a TI-84 you can find p (Z>2) with

normalcdf

Lower 2

Upper 1E99

Mean 0

SD 1

Paste

Result 0.0228