Given AG bisects CD, given IJ bisects CE, given BH bisects ED prove KE = FD

Question

Given AG bisects CD, given IJ bisects CE, given BH bisects ED prove KE = FD

I | A | B |

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K | E | F |

c .------------------------------------------------------------------------------------. D

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J | G | H |

Answer 1

Thank you for the diagram

CE = ED

CK + KE = EF + FD

CK = KE and EF = FD

KE + KE = FD + FD

2 * KE = 2 * FD

KE = FD