Tom K. answered 10/12/20
Knowledgeable and Friendly Math and Statistics Tutor
The length of the major axis is 152,100,000 + 147,100,000 = 299,200,200 kilometers, so the semi-major axis is 299,200,200/2 = 149,600,000 kilometers
Then, the distance of the focus from the center is 149,600,000 - 147,100,000 = 2,500,000
Thus, the eccentricity is 2,500,000/149,600,000 = .0167
The length of the semi-minor axis is √(1496000002 - 25000002) = 149,579,110 km.
The distance between the two foci is 5,000,000 km. That should have been the first question, as that is the same as the difference between the largest and smallest distance. Alternatively, it is 2,500,00 * 2 = 5,000,000 km.