How do I solve this problem

Question

If 1201 J of heat is available what is the mass in grams of Iron ( specific heat = 0.45 J/g C) that can be heated from 22.5 Celsius to 120.0 Celsius

Answer 1

What are you given?

heat = q = 1201 J

specific heat = C = 0.45 J/gº

change in temperature = ∆T = 120 - 22.5 = 97.5º

What are we asked for?

mass = m = ?

Use q = mC∆T and solve for m...

m = q/(C)(∆T)

m = 1201 J/(0.45 J/gº)(97.5º) = 27 g (2 sig. figs.)