Use the provided information to determine ΔHorxn for the following reaction:

Question

Use the provided information to determine ΔH^o_rxn for the following reaction:

 CCl₄ (g) + 4 HCl (g) → CH₄ (g) + 4 Cl₂ (g)

Substance	ΔH°f (kJ/mol)
CH4 (g)	−75.0
CCl4 (g)	−96.0
HCl (g)	−92.0
Cl2(g)	-

Answer 1

CCl₄ (g) + 4HCl (g) ==> CH₄ (g) + 4Cl₂ (g)

-96..........4x-92...............-75...........4x0

So we have ∑products - ∑reactants = ∆Hºrxn

∆Hrxn = -75 - (-96 + -368) = -75 - (-464)

∆Hrxn = -75 + 464

∆Hrxn = 389 kJ/mol