A closed gas system initially has volume and temperature of 5.43L and 831K with the pressure unknown. If the same closed system has values of 616torr, 7310mL and 228.00C, -

Question

what was the initial pressure in atm?

Answer 1

P1 = initial pressure =?

V1 = initial volume = 5.43 L

T1 = initial temp = 831 K

P2 = final pressure = 616 torr

V2 = final volume = 7310 ml x 1 L/1000 ml = 7.310 L

T2 = final temp = 228.00ºC + 273.15 = 501.15 K

Use the Combined Gas Law: P1V1/T1 = P2V2/T2 and solve for P1...

P1 = P2V2T1 / V1T2

P1 = (616 torr)(7.310 L)(831 K / (5.43 L)(501 K)

P1 = 1376 torr = 1380 torr