A gas system has an initial temperature of 119 C with the volume unknown. When the temperature changes to 298.0 K the volume is found to be 4.77 L What was the initial volume in L?

Answer 1

T1 = initial temp = 119ºC + 273 = 392 K

V1 = initial volume = ?

T2 = final temp = 298 K

V2 = final volume = 4.77 L

Since the pressure is assumed to be constant, we can use Charles' Law

V1/T1 = V2/T2 and solving for V1 we have

V2T1/T2 = V1

V1 = (4.77 L)(392 K) / (298 K)

V1 = 6.27 L