A gas system has pressure, volume and moles of 2652 torr, 1670mL and 0.684moles, respectively. What is the temperature in C? (1 atm=760 torr; R = 0.08206 L atm/mol K )

Answer 1

For this problem, we can use the Ideal Gas Law PV = nRT

P = pressure = 2652 torr

V = volume = 1670 ml

n = moles = 0.684 moles

R = gas constant = 0.08206 L atm/K mol

T = temperature = ?

NOTE: the value of R has L (liters) and atm (atmospheres) as part of the units. So we MUST CONVERT volume to liters and pressure to atmospheres before we can use the gas law.

Volume = 1670 ml x 1 L/1000 ml = 1.670 L

Pressure = 2652 torr x 1 atm/760 torr = 3.489 atm

Now using the gas law and solving for T, we have

T = PV/nR = (3.489)(1.670) / (0.684)(0.08206)

T = 103.8 K (NOTE: units of temperature are in Kelvin) = 104K

Now we convert to ºC by subtracting 273º

104 - 273 = -169ºC