For the chemical reaction 3KOH+H3PO4⟶K3PO4+3H2O how many moles of potassium phosphate will be produced from 32.0 g of potassium hydroxide?

Answer 1

3KOH(aq) + H3PO4(aq) ==> K3PO4(aq) + 3H2O(l) ... balanced equation

This balanced equation tells us that ONE mole of K3PO4 will be produced from THREE moles KOH.

So, first we must find out how many moles of KOH we have in our current reaction.

moles KOH = 32.0 g KOH x 1 mol KOH/56.1 g = 0.570 moles KOH present

So, how many moles of K3PO4 can we make?

0.570 mole KOH x 1 mol K3PO4 / 3 moles KOH = 0.190 moles K3PO4 produced