Jon S. answered 10/08/20
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The probability distribution is uniform.
P(0.72 < x < 1.1) = (1.1 - 0.72)/(2 - 0) = 0.38/2 = 0.19
Makaila O.
asked 10/08/20The probability density of a random variable X is given in the figure below.
From this density, the probability that X is between 0.72 and 1.1 is:
Jon S. answered 10/08/20
Patient and Knowledgeable Math and English Tutor
The probability distribution is uniform.
P(0.72 < x < 1.1) = (1.1 - 0.72)/(2 - 0) = 0.38/2 = 0.19
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