Express your answer with the appropriate units.

Question

Iron(III) oxide reacts with carbon monoxide to produce iron and carbon dioxide.

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

What is the percent yield of iron if the reaction of 63.5 g of iron(III) oxide produces 15.4 g of iron?

What is the percent yield of carbon dioxide if the reaction of 73.1 g of carbon monoxide produces 88.5 g of carbon dioxide?

Answer 1

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g) ... balanced equation

To find % yield, we first must find the theoretical yield. Then, % yield = actual yield/theoretical yield x100.

Theoretical yield of Fe using 63.5 g of Fe₂O₃(s):

63.5 g Fe₂O₃(s) x 1 mol Fe₂O₃(s)/159.7 g x 2 mol Fe/ mol Fe₂O₃(s) x 55.8 g Fe/mol Fe = 44.4 g Fe

% yield = 15.4 g / 44.4 g (x100) = 36.7% yield

Theoretical yield of CO₂ using 73.1 g of CO:

73.1 g CO x 1 mol CO / 28.0 g x 3 mol CO₂ / 3 mol CO x 44 g CO₂ /mol CO₂ = 115 g CO₂

% yield = 88.5 g/115 g (x100) = 77.0% yield