J.R. S. answered 10/08/20
Ph.D. University Professor with 10+ years Tutoring Experience
2 H(g) → H2(g) ΔH0rxn = −436 kJ/mol
This tells us that when 2 H combine to form H2(g), 436 kJ/mol are released.
823 kJ x 1 mol H2/436 kJ = 1.8876 moles H2
1.8876 moles H2 x 2.00 g/mol = 3.775 g = 3.78 g of H2 (3 sig. figs.)