Interesting question: Since ABCD is a square, the each angle is a right angle and 90°.
I assume you are looking to solve x and y. If so, solve following system equations to get x and y
3𝑥+5𝑦=90
𝑥−𝑦+20=90
substitution: 3(y+70) + 5y = 90 > y=-15, x=55,
The answers will not apply to angle <C: 4𝑥+3𝑦+16=90.
Therefore, ABCD could not be a square.
If ABCD is quadrilateral polygon, then the sum of the interior angle equals 360° ,
3𝑥+5𝑦+𝑥−𝑦+20+4𝑥+3𝑦+16=360
without any more information, we cannot resolve x and y value.
Olease R.
need help solving to ensure I did the answer correctly10/08/20