J.R. S. answered 10/07/20
Ph.D. University Professor with 10+ years Tutoring Experience
Molar mass of MnSO4·H2O = 151 + 18 = 169 g/mol
0.020 M = 0.020 moles/liter
Since we only need to make 25 ml (0.025 L), we only need...
0.025 L x 0.020 mol/L = 0.000500 moles of MnSO4·H2O
mass needed = 0.000500 moles x 169 g/mol = 0.0845 g = 0.085 g MnSO4·H2O needed (2 sig. figs.)