Calculate the mass of malonic acid

Question

Calculate the mass of malonic acid, CH2(COOH)2, required to make 25 mL of a solution that is 0.15 M in malonic acid.

Answer 1

Molar mass malonic acid = 104 g/mol

0.15 M = 0.15 mol/L

Since we only want to make 25 ml (0.025 L) we only need 0.025 L x 0.15 mol/L = 0.00375 moles malonic acid

mass needed = 0.00375 moles x 104 g/mol = 0.39 g malonic acid needed