Calvin R. answered 10/06/20
Engaging science, math and English tutor and Rhodes Scholar
For this question, you'll need to use the following kinematics equation for constant acceleration:
x = x0 + v0t + 1/2 at2
where x is position, v is velocity, a is acceleration, and t is time. The "0" subscript on x and v, pronounced "nought," means "initial."
So we just need to plug in the values from the problem. Since the airplane starts from rest, the initial velocity is 0:
v0 = 0 m/s
a = 3.00 m/s2
t = 20.0 s
Since displacement, sometimes indicated as "Δx", is the difference between the final position and the initial position, we can rearrange the equation as:
Δx = x – x0 = v0t + 1/2 at2
Δx = v0t + 1/2 at2 = (0)(20.0 s) + 1/2 (3.00 m/s2)(20.0 s)2
Make sure to keep track of your units as you go:
Δx = (1/2 × 3.00 × 20.02) (m/s2 × s2)
= 600. m
So, the displacement of a plane starting from rest in 20.0 s at a constant acceleration of 3.00 m/s2 is 600. m.
P.S. Be sure to retain the correct number of significant figures: in this case, three, since both given values (3.00 and 20.0) have 3 significant figures. The decimal at the end of 600 indicates that the 6, the 0 in the tens place, and the 0 in the ones place are all significant digits, and the answer is accurate within 1 or 2 meters. If we just write "600," we might mean that only 6 is a sig fig, and that the answer has a much greater uncertainty in the realm of ±100 meters.