J.R. S. answered 10/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
Take the weighted average as follows:
(0.75200 * 45.95263) + (0.10900 * 47.94795) + (0.13900 * 49.94479) = 34.556 + 5.2263 + 6.9423 = 46.725
Darragh S.
asked 10/06/20On another planet, the isotopes of titanium have the given natural abundances.
IsotopeAbundanceMass (u) | ||
46Ti | 75.200% | 45.95263 |
48Ti | 10.900% | 47.94795 |
50Ti | 13.900% | 49.94479 |
What is the average atomic mass of titanium on that planet?
J.R. S. answered 10/06/20
Ph.D. University Professor with 10+ years Tutoring Experience
Take the weighted average as follows:
(0.75200 * 45.95263) + (0.10900 * 47.94795) + (0.13900 * 49.94479) = 34.556 + 5.2263 + 6.9423 = 46.725
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