How many liters at STP are in 112 grams of O2 gas?

Answer 1

At STP (standard Temperature and Pressure), recall that 1 mole of any ideal gas occupies 22.4 L.

So, let's first find out how many moles of gas we have...

112 g O₂ x 1 mol O₂/32 g = 3.50 moles of O₂ gas

Now we simply convert that to liters...

3.50 moles x 22.4 L/mol = 78.4 L