About 6% of the population has a particular genetic mutation. 500 people are selected. Find the standard deviation for the number of people with the genetic mutation in such 500 groups of 500

Question

Be as detailed as possible...I'm so lost

Answer 1

Binomial distribution says:

standard deviation = sqrt ( N * p * q)

p = 6% = 0.06

q = 1 - p = 94% = 0.94

standard deviation = sqrt( 500*0.06*0.94) = 5.310367218940701467993571885231

Do you understand why it is Binomial in the first place?

500 trials, the probability of "SUCCESS" ( having the genetic mutation) is 6%