Maya P.

asked • 10/03/20

Le Chatliers Principle

Hi!

I know that Le Chatliers principe states that if we for example increase pressure by decreasing the volume, then the equilibrium will shift to the reaction that gives least moles of gas. Does that only work for homogenous equilibria with only gases or does it work for heterogenous equilibria where for example there are 2 moles of gas and 1 mole of liquid on one side and 3 moles of gas on the other?


Thanks!

1 Expert Answer

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J.R. S. answered • 10/03/20

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It works for any system in which a gas is present, if I understand you question correctly.

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Maya P.

Hi! Thanks, so this system: CaCO3 (s) CaO(s) + CO2 (g), if I increase pressure than the equilibrium will be pushed to the right for 0 moles of gas? PS: Another question please; since this system is heterogeneous, then the increase of CaCO3 or CaO will not affect equilibrium since in heterogeneous equilibria the solids and pure liquids are not counted?
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10/03/20

J.R. S.

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I think the reaction is probably CaCO3 => CaO + CO2 (decomposition of CaCO3). If I'm correct, then increasing the pressure will push the equilibrium to the LEFT. Yes to your 2nd question. The equilibrium expression would simply be Keq = (PCO2) or Keq = [CO2] as solids are not counted.
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10/03/20

Maya P.

oh yes, sorry for typo. Thanks for your answers :D
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10/03/20

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