Blake M. answered 02/16/15
Tutor
New to Wyzant
Math, Science, Industry Experience
Dylan,
I am assuming you are looking for a diagonal, and then the angles between this diagonal and each of two adjacent sides, of the rectangle.
First, lets find the length of the diagonal.
In any right triangle, A^2 + B^2 = C^2, where A & B are the two sides of the rectangle. C is the diagonal, or hypotenuse of the triangle.
Solving, C = sqrt(13 ^ 2 + 16 ^ 2) => C = sqrt (425) = 20.62
Lets call the angle between C and the 16cm side, Theta
We know, from trigonometry, that C * cos(theta) = 16cm
Solving, cos(theta) = 16 / 20.62 = 0.776
Then, theta = arc cos (0.776) = 39.1 degrees
There are now two ways to compute the angle between C and the 13 cm side. One is to realize that the angle between two sides, of the rectangle, are 90 and subtract 39.1 from this, giving 50.9.
The other is to do the same calculation as above, but with the narrower side.
If we call the second angle delta, C * cos(delta) = 13.
cos(delta) = 13 / 20.62 = 0.63, delta = arc cos (0.63) = 50.9
Note that we did not use the sin function to compute delta. If we had, we would have been re-calculating theta, and would have gotten the same answer for theta. We would not have gotten delta.