Yesenia V.
asked • 10/02/20I need help I don’t know how to convert
What is the Temperature of 0.495 more of neon in a 2.00 L vessel at 4.68 atm
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1 Expert Answer
J.R. S. answered • 10/03/20
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Ph.D. University Professor with 10+ years Tutoring Experience
0.495 MOLES of Ne in 2.00 L at 4.68 atm
Use PV = nRT (ideal gas law) and solve for T (temperature)
T = PV/nR = (4.68 atm)(2.00 L) / (0.495 mole)(0.0821 Latm/Kmol)
T = 230K (note the answer is in Kelvin)
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Stanton D.
If there is more neon now, how much was there to begin with?10/03/20