The slope of the segment JK is (6--4)/(-4--24) = 10/20 = 1/2
The slope of the perpendicular bisector is the negative reciprocal of -2/1 = -2
Since it is the perpendicular bisector that line contains the midpoint of segment JK = ((-24 + -4)/2, (-4+6)/2) = (-14,1)
point-slope form is y-y1 = m(x-x1).
m is -2, x1 = -14 and y1 = 1
so y-1 = -2(x+14)
Halle S.
thank you so much for your help! It makes so much more sense now :)10/02/20