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Question

How many liters of flying cats are needed to form 231 L Of sulfur hexafluoride gas if the following reaction takes place at 2.00 atm and 273.15 K?

S(s)+3F2(g)=SF6(g)

Answer 1

Find moles SF6 in 231 L

PV = nRT

n = PV/RT = (2.00 atm)(231 L)/(0.0821)(273.15)

n = 20.6 moles SF6

Now find moles of F2 gas needed (F2 gas = flying cats)

20.6 mol SF6 x 3 mol F2 / mol SF6 = 61.8 moles fluorine gas (flying cats)

Finally, convert this to liters using PV = nRT

V = nRT/P = (61.8)(0.0821)(273.15) / 2

V = 693 L