J.R. S. answered 10/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
From the balanced equation we see the mole ratio of NaOH to H2SO4 is 2:1. We will use this in our dimensional analysis below.
moles NaOH used = 0.12 mol/L x 0.0214 L = 0.002568 moles
moles H2SO4 present = 0.002568 mol NaOH x 1 mol H2SO4 / 2 mol NaOH = 0.001284 moles
Molarity H2SO4 = moles/liter = 0.001284 mol/0.0325 L = 0.0395 M = 0.040 M